Check Euler number

n = 10
 EE = exp(1.0)
 DO i = 1, nn
    E = (1.0 + 1.0/n)**n
    write(*,*) n, E, abs(E-EE)
    n = n*10
 END DO



In [1]:

    
import math



In [3]:

    
math.exp(1)









    Out[3]:





2.718281828459045



In [4]:

    
def euler_n(n):
    return (1+1/n)**n



In [15]:

    
for i in range(1,100000000):
    error=euler_n(i)-math.exp(1)
    #print("error: {}".format(euler_n(i)-math.exp(1)))
print(error)









    



3.063474807163402e-09



In [16]:

    
import numpy as np



In [17]:

    
a=np.array([1,2])
b=np.array([3,4])
np.concatenate((a,b))









    Out[17]:





array([1, 2, 3, 4])



In [ ]: